7y^2+17y=12

Solution for 7y^2+17y=12 equation:

7y^2+17y=12

We move all terms to the left:

7y^2+17y-(12)=0

a = 7; b = 17; c = -12;
Δ = b2-4ac
Δ = 172-4·7·(-12)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-25}{2*7}=\frac{-42}{14}
=-3
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+25}{2*7}=\frac{8}{14}
=4/7
$